NCERT Solutions Class 6 Mathematics Chapter 3 Playing with Numbers – Here are all the NCERT solutions for Class 6 Mathematics Chapter 3. This solution contains questions, answers, images, explanations of the complete Chapter 3 titled Playing with Numbers of Mathematics taught in Class 6. If you are a student of Class 6 who is using NCERT Textbook to study Mathematics, then you must come across Chapter 3 Playing with Numbers. After you have studied lesson, you must be looking for answers of its questions. Here you can get complete NCERT Solutions for Class 6 Mathematics Chapter 3 Playing with Numbers in one place.
NCERT Solutions Class 6 Maths Chapter 3 Playing With Numbers
Here on AglaSem Schools, you can access to NCERT Book Solutions in free pdf for Maths for Class 6 so that you can refer them as and when required. The NCERT Solutions to the questions after every unit of NCERT textbooks aimed at helping students solving difficult questions.
For a better understanding of this chapter, you should also see summary of Chapter 3 Playing With Numbers , Maths, Class 6.
| Class | 6 |
| Subject | Maths |
| Book | Mathematics |
| Chapter Number | 3 |
| Chapter Name |
Playing With Numbers |
NCERT Solutions Class 6 Maths chapter 3 Playing With Numbers
Class 6, Maths chapter 3, Playing With Numbers solutions are given below in PDF format. You can view them online or download PDF file for future use.
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Question & Answer
Q.1: Find the possible factors of 45, 30 and 36
Ans : Missing
Q.2: Write all the factors of the following numbers :
(a) 24
(b) 15
(c) 21
(d) 27
(e) 12
(f) 20
(g) 18
(h) 23
(i) 36
Ans : (a) 24 \( \begin{array} { l } { 24 = 1 \times 24,24 = 2 \times 12, 24 = 3 \times 8 } \\ { 24 = 4 \times 624 = 6 \times 4 } \\ { \therefore \text { Factors of } 24 \text { are } 1,2,3,4,6,8,12 , \text { and } 24 } \end{array} \) (b) 15 \( \begin{array} { l } { 15 = 1 \times 15,15 = 3 \times 5,15 = 5 \times 3 } \\ { \therefore \text { Factors of } 15 \text { are } 1,3,5 , \text { and } 15 } \end{array} \) (c) 21 \( \begin{array} { l } { 21 = 1 \times 21,21 = 3 \times 7,21 = 7 \times 3 } \\ { \therefore \text { Factors of } 21 \text { are } 1,3,7 , \text { and } 21 } \end{array} \) (d) 27 \( \begin{array} { l } { 27 = 1 \times 27,27 = 3 \times 9,27 = 9 \times 3 } \\ { \therefore \text { Factors of } 27 \text { are } 1,3,9 , \text { and } 27 } \end{array} \) (e) 12 \( \begin{array} { l } { 12 = 1 \times 12,12 = 2 \times 6,12 = 3 \times 4,12 = 4 \times 3 } \\ { \therefore \text { Factors of } 12 \text { are } 1,2,3,4,6 , \text { and } 12 } \end{array} \) (f) 20 \( \begin{array} { l } { 20 = 1 \times 20,20 = 2 \times 10,20 = 4 \times 5,20 = 5 \times 4 } \\ { \therefore \text { Factors of } 20 \text { are } 1,2,4,5,10 , \text { and } 20 } \end{array} \) (g) 18 \( \begin{array} { l } { 18 = 1 \times 18,18 = 2 \times 9,18 = 3 \times 6,18 = 6 \times 3 } \\ { \therefore \text { Factors of } 18 \text { are } 1,2,3,6,9 , \text { and } 18 } \end{array} \) (h) 23 \( \begin{array} { l } { 23 = 1 \times 23,23 = 23 \times 1 } \\ { \therefore \text { Factors of } 23 \text { are } 1 \text { and } 23 } \end{array} \) (i) 36 \( \begin{array} { l } { 36 = 1 \times 36,36 = 2 \times 18,36 = 3 \times 12,36 = 4 \times 9 } \\ { 36 = 6 \times 6 } \end{array} \)
Q.3: Write first five multiples of :
(a) 5
(b) 8
(c) 9
Ans : (a) \( \begin{array} { l } { \text 5 \times 1 = 5,5 \times 2 = 10,5 \times 3 = 15,5 \times 4 = 20,5 \times 5 = 25 } \\ { \therefore \text { The required multiples are } 5,10,15,20 , \text { and } 25 . } \end{array} \) (b) \( \begin{array} { l } { \text 8 \times 1 = 8,8 \times 2 = 16,8 \times 3 = 24,8 \times 4 = 32,8 \times 5 = 40 } \\ { \therefore \text { The required multiples are } 8,16,24,32 , \text { and } 40 . } \end{array} \) (c) \( \begin{array} { l } { \text 9 \times 1 = 9,9 \times 2 = 18,9 \times 3 = 27,9 \times 4 = 36,9 \times 5 = 45 } \\ { \therefore \text { The required multiples are } 9,18,27,36 , \text { and } 45 . } \end{array} \)
Q.4: Match the items in column 1 with the items in column 2
\( \begin{array} { l l } { \text { Column } 1 } & { \text { Column } 2 } \\ { \text { (i) } 35 } & { \text { (a) Multiple of } 8 } \\ { \text { (ii) } 15 } & { \text { (b) Multiple of } 7 } \\ { \text { (iii) } 16 } & { \text { (c) Multiple of } 70 } \\ { \text { (iv) } 20 } & { \text { (d) Factor of } 30 }\\ { \text { (v) } 35 } & { \text { (e) Factor of } 50 } \\ & { \text { (f) Multiple of } 20 } \\ \end{array} \)
Ans : \( \begin{array} { l l } { \text { Column } 1 } & { \text { Column } 2 } \\ { \text { (i) } 35 } & { \text { (b) Multiple of } 7 } \\ { \text { (ii) } 15 } & { \text { (d) Factor of } 30 } \\ { \text { (iii) } 16 } & { \text { (a) Multiple of } 8 } \\ { \text { (iv) } 20 } & { \text { (d) Factor of } 20 } \\ { \text { (v) } 25 } & { \text { (e) Factor of } 50 } \end{array} \)
Q.5: Find all the multiples of 9 upto 100.
Ans : \( \begin{array} { l } { 9 \times 1 = 9,9 \times 2 = 18,9 \times 3 = 27,9 \times 4 = 36,9 \times 5 = 45 } \\ { 9 \times 6 = 54,9 \times 7 = 63,9 \times 8 = 72,9 \times 9 = 81,9 \times 10 = 90 } \\ { 9 \times 11 = 99 } \\ { \text { Therefore, the multiples of } 9 \text { up to } 100 \text { are } } \\ { 9,18,27,36,45,54,63,72,81,90 , \text { and } 99 } \end{array} \)
NCERT / CBSE Book for Class 6 Maths
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