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NCERT Solutions Class 11 Maths Chapter 2 Relations And Functions – Here are all the NCERT solutions for Class 11 Maths Chapter 2. This solution contains questions, answers, images, explanations of the complete chapter 2 titled Of Relations And Functions taught in Class 11. If you are a student of Class 11 who is using NCERT Textbook to study Maths, then you must come across chapter 2 Relations And Functions After you have studied lesson, you must be looking for answers of its questions. Here you can get complete NCERT Solutions for Class 11 Maths Chapter 2 Relations And Functions in one place.

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NCERT Solutions Class 11 Maths Chapter 2 Relations And Functions

Here on AglaSem Schools, you can access to NCERT Book Solutions in free pdf for Maths for Class 11 so that you can refer them as and when required. The NCERT Solutions to the questions after every unit of NCERT textbooks aimed at helping students solving difficult questions.

For a better understanding of this chapter, you should also see summary of Chapter 2 Relations And Functions , Maths, Class 11.

Class 11
Subject Maths
Book Mathematics
Chapter Number 2
Chapter Name

Relations And Functions

NCERT Solutions Class 11 Maths chapter 2 Relations And Functions

Class 11, Maths chapter 2, Relations And Functions solutions are given below in PDF format. You can view them online or download PDF file for future use.

Relations And Functions Download

NCERT Solutions for Class 11 Maths Chapter 2 Relations and Functions Download

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Question & Answer

Q.1: If \(\left(\frac{x}{3}+1, y-\frac{2}{3}\right)=\left(\frac{5}{3}, \frac{1}{3}\right)\), find the values of x and y.

Ans : It is given that \(\left(\frac{x}{3}+1, y-\frac{2}{3}\right)=\left(\frac{5}{3}, \frac{1}{3}\right)\). 
Since the ordered pairs are equal, the corresponding elements will also be equal. 
Therefore, \(\frac{x}{3}+1=\frac{5}{3} \quad \text { and } \quad y-\frac{2}{3}=\frac{1}{3}\). 
\(\frac{x}{3}+1=\frac{5}{3}\) 
\(\Rightarrow \frac{x}{3}=\frac{5}{3}-1\) , \(y-\frac{2}{3}=\frac{1}{3}\) 
\(\Rightarrow \frac{x}{3}=\frac{2}{3} \Rightarrow y=\frac{1}{3}+\frac{2}{3}\) 
\(\begin{array}{l}{\Rightarrow x=2 \quad \Rightarrow y=1} \\ {\therefore x=2 \text { and } y=1}\end{array}\) 
Q.2: If the set A has 3 elements and the set B = {3, 4, 5}, then find the number of elements in (A×B).

Ans : It is given that set A has 3 elements and the elements of set B are 3,4, and 5. 
⇒ Number of elements in set B = 3 
Number of elements in (A x B) 
= (Number of elements in A) x (Number of elements in B)
= 3x3 =9 
Thus, the number of elements in (A x B) is 9. 
Q.3: If G = {7, 8} and H = {5, 4, 2}, find G × H and H × G.

Ans : G = {7, 8} and H = {5, 4, 2}
We know that the Cartesian product P × Q of two non-empty sets P and Q is defined as
P × Q = {(p, q): p∈ P, q ∈ Q} 
∴G × H = {(7, 5), (7, 4), (7, 2), (8, 5), (8, 4), (8, 2)} 
H × G = {(5, 7), (5, 8), (4, 7), (4, 8), (2, 7), (2, 8)} 
Q.4: State whether each of the following statements are true or false. If the statement is false, rewrite the given statement correctly. 
(i) If P = {m, n} and Q = { n, m}, then P × Q = {(m, n),(n, m)}.
(ii) If A and B are non-empty sets, then A × B is a non-empty set of ordered pairs (x, y) such that x ∈ A and y ∈ B. 
(iii) If A = {1, 2}, B = {3, 4}, then A × (B ∩ \(\phi\)) = \(\phi\)

Ans : (i) False 
If P = {m, n} and Q = {n, m}, then 
P × Q = {(m, m), (m, n), (n, m), (n, n)} 
(ii) True 
(iii) True 
Q.5: If A = {–1, 1}, find A × A × A.

Ans : It is known that for any non-empty set A, A × A × A is defined as 
A × A × A = {(a, b, c): a, b, c ∈ A} 
It is given that A = {–1, 1} 
∴ A × A × A = {(–1, –1, –1), (–1, –1, 1), (–1, 1, –1), (–1, 1, 1), (1, –1, –1), (1, –1, 1), (1, 1, –1), (1, 1, 1)}

NCERT / CBSE Book for Class 11 Maths

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