NCERT Solutions Class 7 Science Chapter 13 Motion and Time – Here are all the NCERT solutions for Class 7 Science Chapter 13. This solution contains questions, answers, images, explanations of the complete chapter 13 titled Motion and Time of Science taught in class 7. If you are a student of class 7 who is using NCERT Textbook to study Science, then you must come across chapter 13 Motion and Time. After you have studied lesson, you must be looking for answers of its questions. Here you can get complete NCERT Solutions for Class 7 Science Chapter 13 Motion and Time in one place.
NCERT Solutions Class 7 Science Chapter 13 Motion and Time
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| Class | 7 |
| Subject | Science |
| Book | Science |
| Chapter Number | 13 |
| Chapter Name |
Motion and Time |
NCERT Solutions Class 7 Science chapter 13 Motion and Time
Class 7, Science chapter 13, Motion and Time solutions are given below in PDF format. You can view them online or download PDF file for future use.
Motion and Time
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Question & Answer
Q.1: Classify the following as motion along a straight line, circular or oscillatory motion:
(i) Motion of your hands while running.
(ii) Motion of a horse pulling a cart on a straight road.
(iii) Motion of a child in a merry-go-round.
(iv) Motion of a child on a see-saw.
(v) Motion of the hammer of an electric bell.
(vi) Motion of a train on a straight bridge.
Ans : (i) Oscillatory motion While running, the hands move to and fro and repeat their motion after a given interval of time. Hence, it is an oscillatory motion. (ii)Straight line The horse is pulling a cart on a straight road. Therefore, it has a motion along a straight line. (iii)Circular motion Merry-go-round has a circular motion. Therefore, a child sitting inside it will also have a circular motion. (iv) Oscillatory motion The child on a see-saw goes up and down continuously. It oscillates up-down. Therefore, it is an oscillatory motion. (v)OsciIIatory motion The hammer hits the electric bell and vibrates rapidly. Therefore, it is an oscillatory motion. (vi) Straight line The train is moving on a straight bridge. Therefore, it has a motion along a straight line.
Q.2: Which of the following are not correct?
(i) The basic unit of time is second.
(ii) Every object moves with a constant speed.
(iii) Distances between two cities are measured in kilometres.
(iv) The time period of a given pendulum is not constant.
(v) The speed of a train is expressed in m/h.
Ans : (i) Correct Second is the Sl unit of time. (ii) Not correct An object can move with constant or variable speed. (iii) Correct The distance between two cities can be very large. Since kilometre is a bigger unit of distance, the distance between two cities is measured in kilometres. (iv) Not correct Time period of a pendulum depends on the length of the thread. Hence, it is constant for a particular pendulum. (v) Not correct The speed of a train is measured either in km/h or in m/s.
Q.3: A simple pendulum takes 32 s to complete 20 oscillations. What is the time period of the pendulum?
Ans : Number 0T oscillations =20 Total time taken to complete 20 oscillations 32 s
Q.4: The distance between two stations is 240 km. A train takes 4 hours to cover this distance. Calculate the speed of the train.
Ans : Distance between the two stations = 240 km Time taken = 4 h
Q.5: The odometer of a car reads 57321.0 km when the clock shows the time 08:30 AM. What is the distance moved by the car, if at 08:50 AM, the odometer reading has changed to 57336.0 km? Calculate the speed of the car in km/min during this time. Express the speed in km/h also.
Ans : Initial reading of the odometer of the car = 57321.0 km v Final reading of the odometer of the car = 57336.0 km Distance covered by the car = Final reading of the odometer of the car — Initial reading of the odometer of the car = 57336.0 - 57321.0 = 15 km The given car starts at 8:30 a.m. and stops at 8:50 a.m. Therefore, time taken by the car to cover the distance is (8:50- 8:30) min= 20 min Distance covered by the car = 15 km Time taken by the car = 20 minAgain, 60 min=1 h
Time taken by the car =
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